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Estimation Hypothesis and Testing

Essay Instructions:

Complete the following questions in a 1-3-page document formatted per the CSU Global Writing Center (Links to an external site.). Be sure to use Version 1 of Online Statistics: An Interactive Multimedia Course of Study.
Lane, Chapter 7 (Links to an external site.), exercise 25 (Angry Moods Study)
Lane, Chapter 8 (Links to an external site.), exercise 25 (Angry Moods Study)
Lane, Chapter 9 (Links to an external site.), exercise 27 (Angry Moods Study)
Complete parts a - c in the directions above the question.

Essay Sample Content Preview:
#25. Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for men and women are both 20. Assume the Anger-Out scores for both genders are normally distributed. Given this information about the population parameters:
* What is the mean of the sampling distribution of the difference between means? (relevant section)
Ї In order to find the mean from the given, the first thing that must be done is to assume X and Y as the randomly selected anger-out score for men and women, respectively.
Accordingly, we can find the said means by using the formular ОЈ(xМ„ - yМ„) = Ој1- Ој2
ОЈ(xМ„ - yМ„) = Ој1- Ој2 = 2
Therefore, the mean of the sampling distribution of the difference between the means is 2.
* What is the standard error of the difference between means? (relevant section)
Ї Now that we have found that variance and other relevant, we can also find out the standard error for the said formula. Using the formula, в€љ(xМ„ - yМ„)
= в€љ(xМ„ - yМ„)
= в€љ [(20/30) + (20/48)]
= в€љ [0.667 + 0.417]
= в€љ [0.667 + 0.417]
= в€љ 1.083
= 1.041
Therefore, the Standard error between them is 1.041.
* What is the probability that you would have gotten this mean difference (see #24) or less in your sample? (relevant section) (24. What is the mean difference between men and women on the Anger-Out scores?)
Ї The formula to find out the Probability would be based from the answers that were taken above, accordingly,
= P(Mean difference ≤0)
= P(Z ≤ -1.922) = 0.02733197 or 0.273
Therefore, the probability that I would have gotten the mean difference was 0.273 or 27.3%
Ways to improve an angry mood: A look at gender and sports participation Research conducted by: Emily Zitek and Mindy Ater, Rice UniversityCase study prepared by: Emily ZitekOverviewPeople have different ways of improving their mood when angry. We have all seen people punch a wall when mad, and indeed, previous research has indicated that some people aggress to improve their mood (Bushman, Baumeister & Phillips, 2001). What do the top athletes do when angry? Striegel (1994) found that anger often hurts an athlete’s performance and that capability to control anger is what makes good athletes even better. This study adds to the past research and examines the difference in ways to improve an angry mood by gender and sports participation.
The participants were 78 Rice University undergraduates, ages 17 to 23. Of these 78 participants, 48 were females and 30 were males and 25 were athletes and 53 were non-athletes. People who did not play a varsity or club sport we...
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