Heat Capacity and Heat Produced for Coffee Cup Calorimeter

Lab Report
Author Name
Institution Affiliation
Data
Temperature of calorimeter and NaOH (˚C)

31.5°C

ΔT determined from your curve after adding HCl to NaOH(˚C)

32.7

Heat gained by solution (Joules)

2675.2J

Heat gained by calorimeter

355.3J

Total joules released by the reaction

2857.1J

Balanced equation: NaOH(aq) + HCl(aq) --> H2O(l) + NaCl(aq)

The number of moles of HCl in 50mL of 2.0M of your strong acid.

1.0 M

Joules released per mole of HCl consumed

4.273 kJ

Calculation
Part A:
C1. Calculate the heat capacity (C) for your coffee cup calorimeter.
Answer: First of all, we will look at the value of energy lost during this reaction:
q = m Cp ΔT
q = (72.54 g) (4.183 J/g-1 °C-1) (24.2 °C)
q = 7376.22 J
In the next step, we are to calculate the value of energy gained during the reaction:
q = m Cp ΔT
q = (58.84 g) (4.183 J/g-1 °C-1) (24.8 °C)
q = 5818.53 J
The heat capacity of coffee cup calorimeter is as follows:
7376.22 - 5818.53 = 1557.69 J
All of the heat leaving the hot water will go into either the cold water or the coffee cup calorimeter.
-qhot= qcold+ qcup
Becomes