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Chemistry: Questions, Potassium Chloride: KCl and Water
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Answer the questions.
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1 If you have 3 liters of a solution of potassium chloride at a concentration of 2M, what is the solute? What is the solvent? What is the volume of the solution? Express 2M as a fraction.
* Solution: Potassium chloride: KCl and water
Ї Solvent: Water (or aqueous solution)
Ї Solute: KCl = 74.5 grams/mol
н K = 38.1 grams/mol
н Cl = 35.4 grams/mol
* Amount of solution/volume of solution = 3 liters
* Concentration = 2M or 2 mol/l
2 Here are the formula weights for three compounds often used in molecular biology: NaCl, 58.44; Tris base, 121.1; EDTA, 372.2
1 For each of these three compounds, how much solute is required to make 1L of a 1M solution?
* NaCl = 58.44 grams
* Tris Base = 121.1 grams
* EDTA = 372.2 grams
2 For each of these three compounds, how much solute is required to make 0.5m of a 1L solution?
Updated on
* Solution: Potassium chloride: KCl and water
Ї Solvent: Water (or aqueous solution)
Ї Solute: KCl = 74.5 grams/mol
н K = 38.1 grams/mol
н Cl = 35.4 grams/mol
* Amount of solution/volume of solution = 3 liters
* Concentration = 2M or 2 mol/l
2 Here are the formula weights for three compounds often used in molecular biology: NaCl, 58.44; Tris base, 121.1; EDTA, 372.2
1 For each of these three compounds, how much solute is required to make 1L of a 1M solution?
* NaCl = 58.44 grams
* Tris Base = 121.1 grams
* EDTA = 372.2 grams
2 For each of these three compounds, how much solute is required to make 0.5m of a 1L solution?
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