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15 pages/≈4125 words
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APA
Subject:
Mathematics & Economics
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Math Problem
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# Structure Final Math Problem (Math Problem Sample)

Instructions:

these are 15 structures problems, i need them to be completed no matter what, i am not looking for accuracy i just want them to be completed to the best of your ability

source..
Content:
Question 1
(a).Free Body Diagram.
18â€™AR2
40 kip2â€™
2â€™15kip
2â€™
25kip
2â€™
B6â€™
R1
(b).
Reaction 1;
Fy =0,therefore, R1 =40 cos 20 + 15 = 52.59 Kip.
Reaction 2;
â€‘ Fx =0, therefore, R2 = 40 sin 20 + 25 =38.68 KiP.
Question 2.
(a). Pallowable = Fallowable /Area of Cable
Area of Cable = Ï€d2/4 ,={Ï€Ã—(3/4)}/4 = 122.2 KiP.
(b). â€‘ Vertical Forces = 0
â€‘ Fy = 0.
Taking FV to represent vertical components of forces in the cables;
FV = 122.2 cos á¶±
Sum of upward forces = 2 Ã— 122.2 cosá¶±
=244.4 cosá¶±
Therefore; 244.4 cosá¶± = 30
cosá¶± = 30/244.4
á¶± = cos-1 (0.1227)
= 82.94
=83Â°
Question 3.
(a).The tipping point is 8â€™ from the left end of the beam.
Tipping point
12â€™8â€™
(b).Balance of moments about the tipping point.
300lb150lb
10â€™2â€™x
300Ã—2 = (x) Ã— 150
Therefore, x = 4â€™ from the tipping point.
Question 4.
4(a).Force Polygon.
a1
b
2
c3
d
e
f9
(b).Reaction force; R = 4+8+8+8+8
= 36 Kip.
Cable Stay 5 Analysis
20â€™
á¶±=Arctan(20/7)7â€™
=70.71Â°
Vertical component of force in cable stay =4 kip
Force in cable stay -4/siná¶± = 4/sin 70.71
= 4.24 Kip.
Cable Stay 4 Analysis
á¶±= Arctan (20/5) = 78.69Â°
Force in cable stay 4 = 8/sin 78.69
=8.15 kip.
Cable stay 3
á¶±= Arctan(20/3) = 81.47Â°
Force in cable stay 3 =8/sin 81.47 =8.09 kip.
Cable stay 2
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