# Basic Statistics Module 2 Case (Math Problem Sample)

# Module 2 - Case

## Measures of Central Tendency

### Case Assignment

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Problems need to include all required steps and answer(s) for full credit. All answers need to be reduced to lowest terms where possible.

Answer the following problems showing your work and explaining (or analyzing) your results.

Describe the measures of central tendency. Under what condition(s) should each one be used?

Last year, 12 employees from a computer company retired. Their ages at retirement are listed below. First, create a stem plot for the data. Next, find the mean retirement age. Round to the nearest year.

A retail store manager kept track of the number of car magazines sold each week over a 10-week period. The results are shown below.

27 30 21 62 28 18 23 22 26 28

Find the mean, median, and mode of newspapers sold over the 10-week period.

Which measure(s) of central tendency best represent the data?

Name any outliers.

Joe wants to pass his statistics class with at least a 75%. His prior four test scores are 74%, 68%, 84% and 79%. What is the minimum score he needs on the final exam to pass the class with a 75% average?

Nancy participated in a summer reading program. The number of books read by the 23 participants are as follows:

10 9 6 2 5 3 9 1 6 3 10 4 7 6 3 5 6 2 6 5 3 7 2

Number of books read Frequency

1–2

3–4

5–6

7–8

9–10

Complete the frequency table.

Find the mean of the raw data.

Find the median of the raw data.

The chart below represents the number of inches of snow for a seven-day period.

Sunday Monday Tuesday Wednesday Thursday Friday Saturday

2 5 3 10 0 4 2

Find the mean, median, and mode.

Which is the best measure of central tendency?

Remove Wednesday from the calculations. How does that impact the three measures of central tendency?

Describe the effect outliers have on the measures of central tendency.

A dealership sold 15 cars last month. The purchase price of the cars, rounded to the nearest thousand, is represented in the table.

Purchase price Number of cars sold

$15,000 3

$20,000 4

$23,000 5

$25,000 2

$45,000 1

Find the mean and median of the data.

Which measure best represents the data? Use the results to support your answer.

What is the outlier and how does it affect the data?

8. What do the letters represent on the box plot?

Box plot

9. The test scores from a math final exam are as follows:

64 85 93 55 87 90 73 81 86 79

Create a box plot using the data.

Label the five points on the box plot and include numerical answers from part "a."

10. Using the data and results from Question 9, answer the following questions.

What is the median?

What is the range?

What is the interquartile range?

In a short paragraph, describe the data in the box plot.

Submit your work by the module due date. If you are having difficulty, please contact your professor.

# 1.

Measure of central tendency is all about mean, median and mode. Therefore, measure of central tendency is a single value that describes a given set of data by sorting out the central position within that set of data. The mean is used when having both discrete and continuous data. But then, it is worth noting that the mean is greatly affected by the outliers. The median on the other hand, is used when the set of data have outliers. This is because the median is not affected by the outliers. The mode is also used in case we have outliers in a set of data since it does not affect the mode.

#2

Mean = â€‘Xn where X is the age of retirement

Mean = 55+77+64+77+â€¦â€¦+5912 = 79512 =66.25 =66

# 3

* Mean = 27+30+21+62+â€¦2810 =28510 =28.5

Median = arranging the set of data in an ascending order and then the estimate the midst value.

18,21,22,23,26,27,28,28,30,60

We realize the midst values are 26 and 27 thus Median = 26+272 = 26.5

Mode is the appearing data set, thus Mode = 28

* The mean represents the data better because many statistical analyses use the mean as a standard reference point.

* Outliers are 18 and 62

# 4

Mean pass mark target is 75%

Thus Mean = â€‘xn but the prior test sum = 75+68+84+79 = 305

So, 305+x5 =75 this means that 305+x = 75*5

X= 70%

Therefore, he has to

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