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Subject:
Mathematics & Economics
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Topic:

The Major Role of Probability in the Medical Community

Coursework Instructions:

Week 4 Discussion: Probability

Required Resources

 Read/review the following resources for this activity:

  • OpenStax Textbook: Chapter 2, 3

  • Holmes, A., Illowsky, B., & Dean, S. (2017). Introductory business statistics. OpenStax. https://openstax.org/details/books/introductory-business-statistics

    • Lesson

    • Minimum of 1 scholarly source

In your reference for this assignment, be sure to include both your text/class materials AND your outside reading(s).

Initial Post Instructions

Probability plays a major role in the medical community. Diagnoses are based on probabilities. They are really questions or "what if's", and are answered by the probability that the treatment will be the best for the ailment.

Let's look at probability in terms of both the real world and the medical community.

  1. Survey 30 people to find out if they are left-handed or right-handed, and use the following chart to create a contingency table with the information.

  2. Left handed Right handed Total Female Male Total
  1. Answer the following questions about the information in your contingency table:

    1. If a person is randomly selected from the survey participants, what is the probability that the person will be left-handed?

    2. If you randomly choose a female from the people you surveyed, what is the probability that she is left-handed?

    3. What is the odds ratio of choosing a left-handed female?

    4. What is the relative risk of choosing a left-handed female?

    5. Example

 



Green



Blue



Total



Cats



40 (A)



20 (B)



60 (A+B)



Dogs



30 (C)



40 (D)



70 (C+D)



Total



70 (A+C)



60 (B+D)



130 (A+B+C+D)


  1. Probability of Green - (A+C)/(A+B+C+D): 70/130 = 0.54

  2. Probability of Green Cat - A/(A+B): 40/60 = 0.67

  3. Odds Ratio of Green Cat - (A/B)/(C/D) or AD/BC: (4040)/(2030) = 1600/600 = 2.67

  4. Relative Risk of Green Cat - [A/(A+C)]/[B/(B+D)]: (40/70)/(20/60) = 1.71

  5. Skim through at least one of the following articles on left-handed vs. right-handed people from the Chamberlain Library. Answer the following question: How do the probabilities and percentages for your study compare to those in the study you read?

    1. https://search-proquest-com.chamberlainuniversity.idm.oclc.org/nahs/docview/211689160/DB2AB8D1E63B4638PQ/4?accountid=147674 (Links to an external site.)

    2. https://search-proquest-com.chamberlainuniversity.idm.oclc.org/nahs/docview/1326739712/DB2AB8D1E63B4638PQ/10?accountid=147674
Coursework Sample Content Preview:

Probability Problems
Your Name
Subject and Section
Professor’s Name
Date of Submission
1 Survey 30 people to find out if they are left-handed or right-handed, and use the following chart to create a contingency table with the information.
Left handed = 5
Right handed = 25
Total Female = 10
Male Total = 20
1 Answer the following questions about the information in your contingency table:
1 If a person is randomly selected from the survey participants, what is the probability that the person will be left-handed? 0.167
2 If you randomly choose a female from the people you surveyed, what is the probability that she is left-handed? 0.2
3 What is the odds ratio of choosing a left-handed female? 1.416
4 What is the relative risk of choosing a left-handed female? 1.25
Answer
 

Right handed

Left handed

Total

Female

8 (A)

2 (B)

10 (A+B)

Male

17 (C)

3 (D)

20 (C+D)

Total

25 (A+C)

5 (B+D)

30 (A+B+C+D)

* Probability of Left-handed person - (B + D)/(A+B+C+D): 5/30 = 0.167
* Probability of Left-handed female - A/(A+B): 2/10 = 0.2
* Odds Ratio of Left-handed female - (B/A)/(D/C) or CD/AD: (2x17)/(8x3) = 34/24 = 1.416
* Relative Risk of Left-handed female - [B/(B+D)]/[A/(A+C)]: (2/5)/(8/25) = 1.25
1 Skim through at leas...
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